-4m^2+9m+3=-7

Solution for -4m^2+9m+3=-7 equation:

-4m^2+9m+3=-7

We move all terms to the left:

-4m^2+9m+3-(-7)=0

We add all the numbers together, and all the variables

-4m^2+9m+10=0

a = -4; b = 9; c = +10;
Δ = b2-4ac
Δ = 92-4·(-4)·10
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{241}}{2*-4}=\frac{-9-\sqrt{241}}{-8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{241}}{2*-4}=\frac{-9+\sqrt{241}}{-8}
$